Let r=1 radius of quarter circle. See post 172 for definition of angle theta (tan(theta) = pi/2). Complete the square of side r=1. Consider right triangle of sides 1 and tan(theta)-1. Let beta = angle adjacent to side 1 of this triangle. Let delta = pi/2 + beta. Then, tan(delta)=tan(pi/2+beta)=-cot(beta)= =-1/tan(beta). tan(beta)=(tan(theta)-1)/1=pi/2-1 -> tan(delta)= 1/(1-pi/2)=2/(2-pi). Answer C.
Let r=1 radius of quarter circle.
ReplyDeleteSee post 172 for definition of angle theta (tan(theta) = pi/2).
Complete the square of side r=1.
Consider right triangle of sides 1 and tan(theta)-1. Let beta = angle adjacent to side 1 of this triangle.
Let delta = pi/2 + beta. Then,
tan(delta)=tan(pi/2+beta)=-cot(beta)=
=-1/tan(beta).
tan(beta)=(tan(theta)-1)/1=pi/2-1 -> tan(delta)= 1/(1-pi/2)=2/(2-pi).
Answer C.
MIGUE.
you'r right MIGUE. i found the same answer.
ReplyDeleteC
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