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Answer is E.Similar notation that Fox 7, we have:A=Areax=AO, y=BOA = xy/2 = 2/sin(2alpha) -> A'(alpha)=0 ->-> A'(alpha) = -4cos(2alpha)/sen^2(2alpha) = 0 -> alpha = pi/4 -> A(pi/4)= 2 is minimum area of tr. AOB.Note: Second derivative A''(alpha) is positive at alpha = pi/4.
Answer is E.
ReplyDeleteSimilar notation that Fox 7, we have:
A=Area
x=AO, y=BO
A = xy/2 = 2/sin(2alpha) -> A'(alpha)=0 ->
-> A'(alpha) = -4cos(2alpha)/sen^2(2alpha) = 0 -> alpha = pi/4 -> A(pi/4)= 2 is minimum area of tr. AOB.
Note: Second derivative A''(alpha) is positive at alpha = pi/4.