Ahh, yes, expected value of the "ratio of" the bigger area to the smaller one is asked - obviously. Let's give some leeway to minor mistakes in our life. "Perfect" may sometimes be boring!
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Showing posts with label Area. Show all posts
Showing posts with label Area. Show all posts
Monday, January 3, 2011
Fox 324
Before starting to publish received solutions for earlier foxes, let's start with a new one. Here, "random selection" means that points P and Q are uniformly distributed along 2 parallel sides.
Labels:
Area,
Expected value,
Random process,
Square,
Uniform Distribution
Thursday, September 30, 2010
Fox 307 - Solutions
Thursday, September 16, 2010
Wednesday, June 23, 2010
Fox 124 - Solution
Bob Ryden provided this solution to Fox 124.
Thursday, February 18, 2010
Fox 242 - Counterexample-2
Yu claims:
A rectangle is a trapezoid. The shaded area (2 equal triangles) = ¼ of the rectangle.
The above trapezoid has the same area as the rectangle above. As P approaches Q, the height of the upper shaded triangle increases faster than the height of the lower shaded triangle decreases. .: the shaded area > ¼ of the trapezoid.
A rectangle is a trapezoid. The shaded area (2 equal triangles) = ¼ of the rectangle.
Tuesday, February 16, 2010
Wednesday, February 10, 2010
Fox 242 - Counterexample
Bleaug has submitted this counterexample. He smells right :)
Easiest way is to get a counter-example:
assume the upper side of the trapezoid collapses to a single point,
the pink area corresponds to 1/4 of the trapezoid/triangle area.
The (non-empty) blue area is in excess.
Easiest way is to get a counter-example:
assume the upper side of the trapezoid collapses to a single point,
the pink area corresponds to 1/4 of the trapezoid/triangle area.
The (non-empty) blue area is in excess.
Tuesday, January 19, 2010
Fox 230
Labels:
Area,
circle,
Pythagoras,
Rectangle,
semi-circle,
simple proofs,
Square,
Tangent
Wednesday, January 13, 2010
Fox 227
Thursday, December 17, 2009
Fox 212
Wednesday, December 16, 2009
Fox 211
Thursday, December 10, 2009
Fox 206
We have some work on this, but not the final solution.
Please post your result here if you can find one.
Labels:
Area,
Concentric Circles,
Cosine Rule,
Optimization,
right triangle
Sunday, December 6, 2009
Wednesday, December 2, 2009
Tuesday, November 24, 2009
Fox 192
Monday, November 16, 2009
Fox 82
Labels:
Area,
draw lines in the sand,
Quadrilateral,
Triangle
Fox 186
Fox 81
Forget about trigonometry.
Just drawn lines on the sand, like Euclid!
Wednesday, November 4, 2009
Fox 174
Labels:
Area,
Quarter Circle,
Rectangle,
Tangent,
Trigonometry
Sunday, November 1, 2009
Fox 173
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