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Showing posts with label Circle inside Square. Show all posts
Showing posts with label Circle inside Square. Show all posts
Monday, July 26, 2010
Wednesday, June 23, 2010
Fox 124 - Solution
Bob Ryden provided this solution to Fox 124.
Sunday, February 21, 2010
Fox 248 - Solution-2
Bleaug states:
Let's take a, b, c to be the sides of A, B, C squares
By construction, the sum of the two shorter sides of D is equal to c. Same result for E.
All right triangles in the picture are similar, so are D and E.
Similar triangles with equal lengths implies D and E are identical (assertion 2)
The two shorter sides of D and E are a and b. So a+b=c (assertion 1)
Triangle D is to F as G is to E, as b is to a. So F/D=E/G=(b/a)^2. Since E=D we get F.G=E^2=D^2 (assertion 3)
Let's take a, b, c to be the sides of A, B, C squares
By construction, the sum of the two shorter sides of D is equal to c. Same result for E.
All right triangles in the picture are similar, so are D and E.
Similar triangles with equal lengths implies D and E are identical (assertion 2)
The two shorter sides of D and E are a and b. So a+b=c (assertion 1)
Triangle D is to F as G is to E, as b is to a. So F/D=E/G=(b/a)^2. Since E=D we get F.G=E^2=D^2 (assertion 3)
Labels:
Circle inside Square,
proof,
Right Angle,
right triangle,
similarity of triangles,
Solutions
Sunday, November 8, 2009
Wednesday, October 21, 2009
Fox 163
We may be very much different,
but the stories we've been telling
sound so much similar.
--- Himalayan Fox

but the stories we've been telling
sound so much similar.
--- Himalayan Fox
Labels:
British Flag Theorem,
circle,
Circle inside Square,
proof,
Square,
Tangent,
Trigonometry
Wednesday, August 26, 2009
Thursday, August 20, 2009
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