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2pi/4*(1+k+k^2+k^3+k^4+.....)=Lk<1pi/2*(1-(1-k))=L1=k+k^2k=1/2*(sqrt(5)-1)L=pi/(3-sqrt(5)) in shortanswer is B(k : similarity ratio of squares and circles)
Thanks, Newzad - your derivation is superb.Ajit
it is good you have liked it
2pi/4*(1+k+k^2+k^3+k^4+.....)=L
ReplyDeletek<1
pi/2*(1-(1-k))=L
1=k+k^2
k=1/2*(sqrt(5)-1)
L=pi/(3-sqrt(5)) in short
answer is B
(k : similarity ratio of squares and circles)
Thanks, Newzad - your derivation is superb.
ReplyDeleteAjit
it is good you have liked it
ReplyDelete