## Tuesday, June 29, 2010

### Fox 296

This seems to defy the logic. One may ask why not. Looks perfectly possible.
So the claim may very well be wrong.
If you believe so, you may try to find a counter-example.

## Sunday, June 27, 2010

### Fox 295

Let the one who lives, live with an evidence,
Let the one who dies, perish with an evidence.

## Friday, June 25, 2010

### Fox 293 - Solutions

According to the order of submission...
by Bob Ryden: (Ajit commented a very similar one)

by Bleaug:

Two tangents to a given circle define a symmetric 'kite' figure. By construction, the two kites defined by OUV and OTU are isometric because they have identical short legs. Since angles in T, U, V are right angles, blue and green angles are supplemental. Hence, angle a is angle(OUV). From Thales theorem we get cos(a) = 1/3

by Yu:
Several steps remain implicit in the figure. More words may be needed for a formal proof. But the solution holds.

by Binary Descartes:

Common tangents from the same point have equal lengths.
See the two identical deltoids (kites) sharing the same side.
Then cos(a) = e/3e = 1/3.

http://www.8foxes.com/

## Thursday, June 24, 2010

### Fox 294

Let's continue to mess around with this configuration...

## Wednesday, June 23, 2010

### Fox 124 - Solution

Bob Ryden provided this solution to Fox 124.

## Friday, June 18, 2010

### Fox 293

The options are corrected below.
There are about 5 different solutions, that we can post in coming days.

## Tuesday, June 1, 2010

### Fox 291

Not much time to update the blog. But, let's throw this to the public knowledge.
Note: when 3 concentric arcs are given, their center can be identified easily.
(which is a nice exercise and easy by itself).
Let us know if you have a solution.

Aaaah, one more detail. More than one equilaterals should be drawn on 3 concentric circles. Take the figure as it looks and do not go for the "other" equilateral. Let the simplicity ring over the land, in the morning... and during the night...