Wednesday, April 21, 2010

Fox 277

This is a strong statement that does not depend on the type of ellipse.
Has anybody seen something similar anywhere else?
http://www.8foxes.com/

2 comments:

  1. 1)if one tangent is // to the y-axis,the other is // to the x-axis,we have the points:
    (a,b); (a,-b);(-a,b);(-a,-b)
    2)the line y=px+m is tangent to the ellipse,if and only if the discriminant of
    x²/a²+(px+m)²/b²-1=0
    is 0
    a²p²+b²-m²=0
    let be P(z,t)
    for the tangents passing trough P
    m=t-mz
    p is solution of
    a²p²+b²-(t-pz)²=0
    p²(a²-z²)+2ptz+b²-t²=0
    the tangents are perpendicular: pp'=-1
    t²+z²=a²+b²
    3)P maps a circle with radius r²=a²+b²

    ReplyDelete
  2. I see no problem. Great use of analytic geometry! Good work!

    ReplyDelete