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I don't quite understand where I'm making an error. The circle concerned will have a radius of 1/√3 and hence the required length of arc =(1/√3)(5∏/3)= 5∏/3√3. Isn't that so?Ajit
r=1
That's right - i was looking at the wrong triangle!But still angle = 2∏ - ∏/3 = 5∏/3 or what?
5pi/3
Sorry, my mistake. But the answer is not 5pi/3. Let me update the question...
Correction;The total length of the trajectory is 2 x 5pi/3 = 10pi/3.2 x because of 2 major arcs, one on each side of the line.-YU
I don't quite understand where I'm making an error. The circle concerned will have a radius of 1/√3 and hence the required length of arc =(1/√3)(5∏/3)= 5∏/3√3. Isn't that so?
ReplyDeleteAjit
r=1
ReplyDeleteThat's right - i was looking at the wrong triangle!But still angle = 2∏ - ∏/3 = 5∏/3 or what?
ReplyDelete5pi/3
ReplyDeleteSorry, my mistake. But the answer is not 5pi/3. Let me update the question...
ReplyDeleteCorrection;
ReplyDeleteThe total length of the trajectory is 2 x 5pi/3 = 10pi/3.
2 x because of 2 major arcs, one on each side of the line.
-YU