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Translate parabola to place vertex at (0,0).y = ax^2 and y = r-V(r^2-x^2).Bob Ryden's method: r-V(r^2-x^2) >= ax^2, simplify to ax^2 >= (2ar-1)/a.Since ax^2 >= 0, .: the greatest (2ar-1)/a is 0..: ar = 0.5, hence ad = 1. Yu
Perfect!Thank Yu :)
Translate parabola to place vertex at (0,0).
ReplyDeletey = ax^2 and y = r-V(r^2-x^2).
Bob Ryden's method: r-V(r^2-x^2) >= ax^2, simplify to ax^2 >= (2ar-1)/a.
Since ax^2 >= 0, .: the greatest (2ar-1)/a is 0.
.: ar = 0.5, hence ad = 1. Yu
Perfect!
ReplyDeleteThank Yu :)