Bleaug adds new meaning to "laziness". Hmmm, do your lazy tricks lazy scientists to solve this one, huh? Although not confirmed, the similarity of the terms with Fox 3 is striking. Enjoy...
Key words: Geometry, Unusual geometry, Math, Physics, Chemistry, High school, Geometry Olympiads, Free Geometry, Euclidean Geometry, Calculus, Geometric Construction. Oh yes, going-nowhere discussions, haikus, and poems too.
Showing posts with label right triangle. Show all posts
Showing posts with label right triangle. Show all posts
Sunday, November 14, 2010
Wednesday, June 23, 2010
Fox 124 - Solution
Bob Ryden provided this solution to Fox 124.
Sunday, February 21, 2010
Fox 248 - Solution-2
Bleaug states:
Let's take a, b, c to be the sides of A, B, C squares
By construction, the sum of the two shorter sides of D is equal to c. Same result for E.
All right triangles in the picture are similar, so are D and E.
Similar triangles with equal lengths implies D and E are identical (assertion 2)
The two shorter sides of D and E are a and b. So a+b=c (assertion 1)
Triangle D is to F as G is to E, as b is to a. So F/D=E/G=(b/a)^2. Since E=D we get F.G=E^2=D^2 (assertion 3)
Let's take a, b, c to be the sides of A, B, C squares
By construction, the sum of the two shorter sides of D is equal to c. Same result for E.
All right triangles in the picture are similar, so are D and E.
Similar triangles with equal lengths implies D and E are identical (assertion 2)
The two shorter sides of D and E are a and b. So a+b=c (assertion 1)
Triangle D is to F as G is to E, as b is to a. So F/D=E/G=(b/a)^2. Since E=D we get F.G=E^2=D^2 (assertion 3)
Labels:
Circle inside Square,
proof,
Right Angle,
right triangle,
similarity of triangles,
Solutions
Friday, February 19, 2010
Thursday, February 18, 2010
Fox 248
Never delay a good idea.
Once you let it go,
it may never have a chance to resurrect.
--- Himalayan Fox
Labels:
proof,
Right Angle,
right triangle,
similarity of triangles,
Square
Wednesday, February 17, 2010
Tuesday, December 22, 2009
Fox 218
Labels:
3 parallel lines,
Optimization,
perimeter,
right triangle
Thursday, December 10, 2009
Fox 206
We have some work on this, but not the final solution.
Please post your result here if you can find one.
Labels:
Area,
Concentric Circles,
Cosine Rule,
Optimization,
right triangle
Wednesday, November 25, 2009
Tuesday, November 24, 2009
Fox 192
Monday, November 23, 2009
Sunday, November 22, 2009
Saturday, November 21, 2009
Fox 189
Labels:
3 parallel lines,
Optimization,
right triangle,
Trigonometry
Sunday, November 1, 2009
Fox 173
Saturday, October 31, 2009
Fox 172
Simple beginnings...
Sunday, October 25, 2009
Fox 166
Wednesday, August 26, 2009
Thursday, August 20, 2009
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