Long time no see!!!
HELLO WORLD!!!
Hope everybody is doing alright.
Yeah, sure love each other, especially those who really need to be loved!
Let me now take another long break :)
Showing posts with label Right Angle. Show all posts
Showing posts with label Right Angle. Show all posts
Thursday, March 17, 2016
Sunday, February 21, 2010
Fox 248 - Solution-2
Bleaug states:
Let's take a, b, c to be the sides of A, B, C squares
By construction, the sum of the two shorter sides of D is equal to c. Same result for E.
All right triangles in the picture are similar, so are D and E.
Similar triangles with equal lengths implies D and E are identical (assertion 2)
The two shorter sides of D and E are a and b. So a+b=c (assertion 1)
Triangle D is to F as G is to E, as b is to a. So F/D=E/G=(b/a)^2. Since E=D we get F.G=E^2=D^2 (assertion 3)
Let's take a, b, c to be the sides of A, B, C squares
By construction, the sum of the two shorter sides of D is equal to c. Same result for E.
All right triangles in the picture are similar, so are D and E.
Similar triangles with equal lengths implies D and E are identical (assertion 2)
The two shorter sides of D and E are a and b. So a+b=c (assertion 1)
Triangle D is to F as G is to E, as b is to a. So F/D=E/G=(b/a)^2. Since E=D we get F.G=E^2=D^2 (assertion 3)
Thursday, February 18, 2010
Fox 248
Never delay a good idea.
Once you let it go,
it may never have a chance to resurrect.
--- Himalayan Fox
Monday, January 25, 2010
Friday, November 20, 2009
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