Wednesday, December 16, 2009

Fox 211

3 comments:

  1. See Fox 209 for definitions:

    A(ADS) + A(BER) = A(APB)/4, because DS=ER =(PH3)/2, and AS + BR = a2 + q2 = AB/2
    A(ADM) + A(CFN) = A(APC)/4, by DM = FN = (PH1)/2 , c2+s2 =AC/2

    A(CFP) + A(BEQ) = A(BPC)/4, by FP = EQ = (PH2)/2, b2 + r2 = BC/2,

    A(APB)+A(APC)+A(BPC) = A(ABC),

    shaded area = A(ABC) - A(ABC)/4 = 3*A(ABC)/4.

    MIGUE.

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  2. The three kites at the corners tile a similar copy of the original ABC reduced to half, no matter what is the shape of ABC.

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