Monday, December 14, 2009

Fox 207

4 comments:

  1. By Phytagoras theorem it can be prove;
    a^2+b^2+c^2=q^2+r^2+s^2
    (a^2-q^2)+(b^2-r^2)+(c^2-s^2)=0
    Let
    a+q = b+r = s+c = x
    (a-q)x+(b-r)x+(c-s)x=0
    a+b+c=q+r+s

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  2. Very good! But what about "just drawing lines in the sand" ? There is a geometric solution without any equation - or should say with simple additions...

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  3. draw lines from point P, parallel to three sides. additional equilaterals will be formed. simple equalities proves the relationship. a nice problems! thanks.

    -binary

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