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A:(a,8),B:(0,0) & C:(c,-28). AC=BC gives c=(a^2+512)/(2a) and area =(1/2)((a^2+512)(8)/(2a)+28a) which when minimized yields a=8 giving, A(min)=256 or Option C.Ajit
A:(a,8),B:(0,0) & C:(c,-28). AC=BC gives c=(a^2+512)/(2a) and area =(1/2)((a^2+512)(8)/(2a)+28a) which when minimized yields a=8 giving, A(min)=256 or Option C.
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