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A=B, then areas of 2 right triangles with angles 2theta and theta have the same area, which can be written as f(theta). That is:(1/2)cos(2theta)sin(2theta)=(1/2)cos(theta)sin(theta)which should give cos(2theta)=1/2gives the answer, C.
A=B, then areas of 2 right triangles with angles 2theta and theta have the same area, which can be written as f(theta). That is:
ReplyDelete(1/2)cos(2theta)sin(2theta)=(1/2)cos(theta)sin(theta)
which should give cos(2theta)=1/2
gives the answer, C.