Tuesday, October 20, 2009

Fox 162

http://www.8foxes.com/












7 comments:

  1. This comment has been removed by a blog administrator.

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  2. http://img508.imageshack.us/img508/2918/1001096.gif
    there is no solution for sinA, sin4A, sin2A, sin3A bigger than zero

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  3. newzad,
    http://img508.imageshack.us/img508/2918/1001096.gif

    is not openning.

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  4. I got it now. It's openning.
    So, there is a solution but it is not geometrically constructable.

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  5. if the first link does not work
    try:
    http://i33.tinypic.com/2co1swi.gif
    or
    http://img273.yukle.tc/images/9787klh.gif

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  6. I think the answer is 36.
    because for A=45, sin4A=0

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  7. But sin4A=0 is constructable. Means both squares are sharing a corner. So, both solutions hold.

    ReplyDelete