The three triangles around this square are similar. Call the side of the square DEFG, with DG on AB, E on AC and F on BC. Then: EC = 2/sqrt(5)*x and AE = sqrt(5)*x AE+EC = AC = 2 so x = 2/7*sqrt(5) and area DEFG = x^2 = 20/49.
Now we watch any right-angled triangle similar to ABC,with a square in the right angle. When the square had sides x, then it's easy to see that the two remaining triangles are similar with the original triangle, one with factor 2/3 and the other with factor 1/3. And it follows that the side x = hypothenusa/(3/2*sqrt(5)) = 2/(3sqrt(5)) * hypothenusa.
Now we distinguish between the left and right side of the figure.
Right side: In every step the triangle gets smaller with factor 1/3, so every square gets smaller with factor 1/3. The first square has side x0 = 2/(3sqrt(5))*BF = 2sqrt(5)/21 and area (x0)^2=20/441. The areas of the squares on the right side give a geometric sequence, with area An = 20/441*(1/9)^n. The total area of the squares on the right side is equal to Sum(n=0 to infinity)An = 20/441*9/8 = 5/98
Left side: The first square has side 2/(3sqrt(5))*AE = 4sqrt(5)/21 and area 80/441. The area give a geometric sequence: Bn = 80/441*(4/9)^n so the total area of the squares on the lift side is equal to 80/441*9/5 = 16/49
The total sum of the areas of all squares = 20/49 + 16/49 + 5/98 = 77/98 = 11/14
The answer is A.
So also: http://home.kpn.nl/henkreuling/solutions8foxes/132_8foxes_solution.pdf
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First we watch the biggest square in the middle.
ReplyDeleteThe three triangles around this square are similar.
Call the side of the square DEFG, with DG on AB, E on AC and F on BC.
Then: EC = 2/sqrt(5)*x and AE = sqrt(5)*x
AE+EC = AC = 2 so x = 2/7*sqrt(5) and area DEFG = x^2 = 20/49.
Now we watch any right-angled triangle similar to ABC,with a square in the right angle.
When the square had sides x, then it's easy to see that the two remaining triangles are similar with the original triangle, one with factor 2/3 and the other with factor 1/3.
And it follows that the side x = hypothenusa/(3/2*sqrt(5)) = 2/(3sqrt(5)) * hypothenusa.
Now we distinguish between the left and right side of the figure.
Right side:
In every step the triangle gets smaller with factor 1/3, so every square gets smaller with factor 1/3. The first square has side x0 = 2/(3sqrt(5))*BF = 2sqrt(5)/21 and area (x0)^2=20/441.
The areas of the squares on the right side give a geometric sequence, with area An = 20/441*(1/9)^n.
The total area of the squares on the right side is equal to Sum(n=0 to infinity)An = 20/441*9/8 = 5/98
Left side:
The first square has side 2/(3sqrt(5))*AE = 4sqrt(5)/21 and area 80/441.
The area give a geometric sequence: Bn = 80/441*(4/9)^n so the total area of the squares on the lift side is equal to 80/441*9/5 = 16/49
The total sum of the areas of all squares = 20/49 + 16/49 + 5/98 = 77/98 = 11/14
The answer is A.
So also: http://home.kpn.nl/henkreuling/solutions8foxes/132_8foxes_solution.pdf
Thank you for the solution Henkie. This had been remaining unsolved for more than a year.
ReplyDeleteDo not use all of these Private Money Lender here.They are located in Nigeria, Ghana Turkey, France and Israel.My name is Mrs.Ramirez Cecilia, I am from Philippines. Have you been looking for a loan?Do you need an urgent personal or business loan?contact Fast Legitimate Loan Approval he help me with a loan of $78.000 some days ago after been scammed of $19,000 from a woman claiming to be a loan lender from Nigeria but i thank God today that i got my loan worth $78.000.Feel free to contact the company for a genuine financial call/whats-App Contact Number +918929509036 Email:(fastloanoffer34@gmail.com)
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