**Fox 316 Solution:**

Bleaug:

"I couldn't get a pure geometric demonstration of these two problems. At best, with some lazy observations you are able to show that for both #316 and #318, maximum area is achieved for P midpoint of BC:

a) angle(QPR) in P remains constant when P varies

b) PR/PB is constant

c) PQ/PC is constantHence area(PQR) is proportional to PB.PC which is maximized when P is the midpoint of BC.

The rest is obtained by calculus."

**Fox 318 Solution:**

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