Monday, February 28, 2011

Fox 331

Here is a simple contruction problem.
http://www.8foxes.com/

12 comments:

  1. ABCD the quadrilaterl
    E midpoint of AB;F midpoint of CD
    G midpoint of EF

    ReplyDelete
  2. No, this won't work.

    ReplyDelete
  3. the first answer works
    other solutions:
    I midpoint of AD;J midpoint of BC
    G midpoint of IJ
    or
    K midpoint of AC,L midpoint of BD
    G midpoint of KL
    and the 3 ways give the same point G!
    anonymous1

    ReplyDelete
  4. theorem
    the centroid of the vertices of a quadrilateral
    is the midpoint of the lines joining the midpoint of opposite sides,it is also the midpoint of the line joining the midpoint of the diagonals
    anonymous 1

    ReplyDelete
  5. hmmm ok! there are three possible interpretations of problem statement:
    I1) centroid of 4 equal 0-dimensional masses at quadrilateral vertices
    I2) centroid of 4 homogeneously massive 1-dimensional lines forming the given quadrilateral
    I3) centroid of a homogeneously massive 2-dimensional quadrilateral.

    @Anonymous 1: your solution solves I1 only

    I highly suspect that initial 8foxes intention was I3. Anyway, all three interpretations have a construction solution...

    ReplyDelete
  6. "I highly suspect that initial 8foxes intention was I3. Anyway, all three interpretations have a construction solution..."

    Correct. Slight coloring of the quadrilateral implies that.

    ReplyDelete
  7. I2
    the centroid of a massive line is the midpoint
    with mass proportional to the length l
    let be A',B',C',D' the midpoints of the sides a,b,c,d
    we must find K center of the point masses (A',a),(B',b)
    A'K=a/(a+b)A'B'
    this can be done with parallel lines
    L center of (C',c)and (D',d)
    G2 is the centroid of (K,a+b),(L,c+d)

    I3
    the center of gravity of an homogenious triangle is the centroid with a mass proportional to the aera
    each diagonal divides ABCD into 2 triangles
    with centroids C1,C2(first diagonal),C3,C4(second
    diagonal)
    G3 lies on the lines C1C2 and C3C4
    G3 is the intersection of this lines
    (thank you for the hints)
    anonymous1

    ReplyDelete
  8. The centroid of the vertices of a quadrilateral occurs at the point of intersection of the bimedians (i.e., the lines M(AB)-M(CD) and M(AD)-M(BC) joining pairs of opposite midpoints) (Honsberger 1995, pp. 36-37). In addition, it is the midpoint of the line M(AC)-M(BD) connecting the midpoints of the diagonals AC and BD (Honsberger 1995, pp. 39-40).

    http://mathworld.wolfram.com/Quadrilateral.html

    ReplyDelete
  9. There is a nice animation in Joe Wilson's page.
    See here:

    http://jwilson.coe.uga.edu/emt668/EMT668.Folders.F97/Patterson/EMT%20669/centroid%20of%20quad/Centroid.html

    ReplyDelete
  10. The name of the guy is Jim Wilson. Sorry about that...

    ReplyDelete
  11. this simple construction of G3
    M midpoint of diagonal BD
    O intersection of the diagonals
    on diagonal AC,AN=CO
    then MG=1/3 MN
    Essai sur la determination des centres de gravité
    Hyacinthe Celestin Gaubert (1839)p27
    anonymus1

    ReplyDelete
  12. Do not use all of these Private Money Lender here.They are located in Nigeria, Ghana Turkey, France and Israel.My name is Mrs.Ramirez Cecilia, I am from Philippines. Have you been looking for a loan?Do you need an urgent personal or business loan?contact Fast Legitimate Loan Approval he help me with a loan of $78.000 some days ago after been scammed of $19,000 from a woman claiming to be a loan lender from Nigeria but i thank God today that i got my loan worth $78.000.Feel free to contact the company for a genuine financial call/whats-App Contact Number +918929509036 Email:(fastloanoffer34@gmail.com)

    ReplyDelete