Monday, August 23, 2010

Fox 306

Answer is not confirmed yet.

2 comments:

  1. let be ABCD the great square,EFGH the little square,r the rotation by 90 about E
    the coordinates are:
    A(0,0);B(s,0);C(s,s),D(0,s)
    E(a,b);F(c,d)
    H=r(F)
    H(a+b-d,b+c-a)
    G(b+c-d,c+d-a)
    Now it's easy to find
    n²+l²=AE²+CG²=BF²+DH²=m²+k²

    ReplyDelete
  2. http://geometri-problemleri.blogspot.com.es/2012/09/problem-110-ve-cozumu.html

    ReplyDelete