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didnt get which distance is 3?
The distance between the point the top brick touches to the wall, and the top-right corner of the bottom-brick is 3.
ok.thanks....
i dont know how to draw the figure.but i m posting my solution...i will try to explain the figurelet width=a length=b3 triangles which are formed.triangle ABC AB=sqrt(a^2-1)AC=aBC=1triangle PCDPC=bCD=b-1PD=3triangle PEFPE=sqrt(a^2-1)PF=aFE=1triangles ABC and PEF are congruenttriangles ABC and PCD are similar.AB/CD=AC/CP=BC/DPsqrt(a^2-1)/(b-1)=a/b=1/3solving....we get a=5/3sqrt(a^2-1)=4/3soh=5/3+3+4/3=6option 1 is correct.
Looks correct. If you send us your figure, we can try to find a way to post it. Thank you.
Thank you vinay. We received it and will process it in the following days. Great work!--------Vinay says:i have sent the answer with the fig to...have u received it?....
didnt get which distance is 3?
ReplyDeleteThe distance between the point the top brick touches to the wall, and the top-right corner of the bottom-brick is 3.
ReplyDeleteok.thanks....
ReplyDeletei dont know how to draw the figure.
ReplyDeletebut i m posting my solution...
i will try to explain the figure
let width=a
length=b
3 triangles which are formed.
triangle ABC
AB=sqrt(a^2-1)
AC=a
BC=1
triangle PCD
PC=b
CD=b-1
PD=3
triangle PEF
PE=sqrt(a^2-1)
PF=a
FE=1
triangles ABC and PEF are congruent
triangles ABC and PCD are similar.
AB/CD=AC/CP=BC/DP
sqrt(a^2-1)/(b-1)=a/b=1/3
solving....
we get
a=5/3
sqrt(a^2-1)=4/3
so
h=5/3+3+4/3=6
option 1 is correct.
Looks correct. If you send us your figure, we can try to find a way to post it. Thank you.
ReplyDeleteThank you vinay. We received it and will process it in the following days. Great work!
ReplyDelete--------
Vinay says:
i have sent the answer with the fig to...
have u received it?
....