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Let a to e be the radii of the semi-circles. Hence e^2=c*d. Now C+D+2E = ∏(c^2+d^2+2e^2)=∏(c^2+d^2+2cd)=(c+d)^2 = ∏(a^2+b^2) = A+BAjit
Yep, that's the way it is.
Let a to e be the radii of the semi-circles. Hence e^2=c*d. Now C+D+2E = ∏(c^2+d^2+2e^2)=∏(c^2+d^2+2cd)=(c+d)^2 = ∏(a^2+b^2) = A+B
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Yep, that's the way it is.
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