Monday, January 25, 2010

Fox 234

2 comments:

  1. Let a to e be the radii of the semi-circles. Hence e^2=c*d. Now C+D+2E = ∏(c^2+d^2+2e^2)=∏(c^2+d^2+2cd)=(c+d)^2 = ∏(a^2+b^2) = A+B
    Ajit

    ReplyDelete