tag:blogger.com,1999:blog-6500033298667240354.post7384319099346141634..comments2024-02-19T00:34:12.578-08:00Comments on Always Creative Geometry Problems plus Occasionally Annoying Philosophy: Fox 2598foxeshttp://www.blogger.com/profile/09567328431908997738noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-6500033298667240354.post-87872914232153059052010-03-04T21:15:11.556-08:002010-03-04T21:15:11.556-08:00By Stewart's Theorem: AD^2+ 4=2(AE^2+x^2)
and ...By Stewart's Theorem: AD^2+ 4=2(AE^2+x^2)<br />and AE^2+1=2(AD^2+x^2) if BD=DE=EC=x. Eliminate x from the two equationa and use AD + AE = 2 to obtain AD = 3/4 and AE = 5/4 and this gives x^2 = 23/32. Now Tr. ADE gives: 23/32 = 9/16 + 25/16 - 2(3*5*/16)cos(Φ) or cos(Φ) = 3/4<br />AjitAjithttps://www.blogger.com/profile/00611759721780927573noreply@blogger.com